例句與造句

1. The first problem with this is that the coefficient field for a Weil cohomology theory cannot be the rational numbers.
2. When the purpose is to describe the solution set of in the algebraic closure of its coefficient field, those simpler systems are regular chains.
3. The same argument eliminates the possibility of the coefficient field being the reals or the " p "-adic numbers, because the quaternion algebra is still a division algebra over these fields.
4. The endomorphism ring of this is an order in a quaternion algebra over the rationals, and should act on the first cohomology group, which should be a 2-dimensional vector space over the coefficient field by analogy with the case of a complex elliptic curve.
5. For arbitrary input system of polynomial equations and inequations ( with rational number coefficients or with coefficients in a prime field ) one can use the command " RegularChains [ Triangularize ] " for computing the solutions whose coordinates are in the algebraic closure of the coefficient field.
6. It's difficult to find coefficient field in a sentence. 用coefficient field造句挺難的
7. Note that the field " K " is not to be confused with " k "; the former is a field of characteristic zero, called the " coefficient field ", whereas the base field " k " can be arbitrary.
8. In both cases, the hardest part of Cohen's proof is to show that the complete Noetherian local ring contains a "'coefficient ring "'( or "'coefficient field "'), meaning a complete discrete valuation ring ( or field ) with the same residue field as the local ring.
9. However it does not eliminate the possibility that the coefficient field is the field of " l "-adic numbers for some prime " l " ` " " p ", because over these fields the division algebra splits and becomes a matrix algebra, which can act on a 2-dimensional vector space.